POL Mickaël
203c423f19
- Unit : domain (GaugeCalculator, Enclos, Dragodinde, XpTable, Race, Tier...) - Unit : application (commands, queries, CommandBus) - Fonctionnel : breeding-workflow, enclos-management, timer-workflow - Régression : gauge-tier, gauge-recharge, xp-timer, level-target, breeding - E2E Playwright + Electron : navigation, timer, recharge jauge, accouplement, persistance des données Co-Authored-By: Claude Opus 4.6 <noreply@anthropic.com>
59 lines
2.3 KiB
TypeScript
59 lines
2.3 KiB
TypeScript
import { describe, it, expect } from 'vitest';
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import { simulateStock } from '@domain/services/StockSimulator';
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import { BREEDING_RECIPES } from '@domain/value-objects/Race';
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describe('Régression : simulation inventaire identique au monolithe', () => {
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it('8 Rousse (4♂/4♀) + 8 Dorée (4♂/4♀) + 8 Amande (4♂/4♀) → 20 bébés sur 4 générations', () => {
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const r = simulateStock({
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Rousse: { m: 4, f: 4 },
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Dorée: { m: 4, f: 4 },
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Amande: { m: 4, f: 4 },
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});
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// Gen2 : 3 croisements × 4 bébés = 12
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const gen2 = r.crossings.filter(c => c.gen === 2);
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expect(gen2).toHaveLength(3);
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expect(gen2.map(c => c.baby).sort()).toEqual(
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['Amande et Dorée', 'Amande et Rousse', 'Dorée et Rousse'],
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);
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for (const c of gen2) expect(c.count).toBe(4);
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// Gen3 : Ebène×2 + Indigo×2 = 4
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const gen3 = r.crossings.filter(c => c.gen === 3);
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expect(gen3).toHaveLength(2);
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expect(gen3.find(c => c.baby === 'Ebène')!.count).toBe(2);
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expect(gen3.find(c => c.baby === 'Indigo')!.count).toBe(2);
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// Gen4 : Ebène et Indigo×2
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const gen4 = r.crossings.filter(c => c.gen === 4);
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expect(gen4).toHaveLength(1);
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expect(gen4[0]!.baby).toBe('Ebène et Indigo');
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expect(gen4[0]!.count).toBe(2);
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// Gen5 : Orchidée×2 (Pourpre reçoit 0 car EI alloué à floor(1/2)=0)
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const gen5 = r.crossings.filter(c => c.gen === 5);
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expect(gen5).toHaveLength(1);
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expect(gen5[0]!.baby).toBe('Orchidée');
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expect(gen5[0]!.count).toBe(2);
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expect(r.crossings.reduce((s, c) => s + c.count, 0)).toBe(20);
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});
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it('la recette Ebène est Amande et Dorée + Dorée et Rousse (pas Amande et Rousse)', () => {
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expect(BREEDING_RECIPES['Ebène']).toEqual(['Amande et Dorée', 'Dorée et Rousse']);
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});
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it('l\'algorithme glouton aurait donné 8 bébés sur 1 seule race — la version proportionnelle donne 12 sur 3 races', () => {
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const r = simulateStock({
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Rousse: { m: 4, f: 4 },
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Dorée: { m: 4, f: 4 },
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Amande: { m: 4, f: 4 },
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});
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// Vérifier qu'on ne voit PAS un seul croisement avec 8 bébés
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for (const c of r.crossings.filter(x => x.gen === 2)) {
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expect(c.count).toBeLessThanOrEqual(4);
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}
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expect(r.crossings.filter(c => c.gen === 2)).toHaveLength(3);
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});
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});
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